In the circuit shown in the figure the emf of the battery is 9 V and its internal resistance is 15 
. The two identical voltmeters can be considered ideal. Let 
and 
be the readings of 
voltmeter when switch is open and closed respectively. Similarly, 
and 
be the readings of 
voltmeter when switch is open and closed respectively.
Column I | Column II | ||
I | P | 1 V | |
II | Q | 2 V | |
III | R | 3 V | |
IV | S | 4 V |
Now match the given columns and select the correct option from the codes given below. Codes;
Text Solution
Verified by ExpertsB
Since voltmeters are ideal, so no current flows through voltmeters. Now current I through resistances.
Potential difference across 
This potential will be divided equally between 
and 
. So 
After closing the switch, current will remain same. But Now
. across 
across 2 
Hence [(I)‐(R)] [(II)‐(Q)] [(III)‐(R)] [(IV)‐(S)]
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